21:35:00 05/08/2011
Giải hệ nè (x+1)(y+1)+1=(x^2+x+1)(y^2+y+1) và y=x^3-x^2+1
07:20:00 06/08/2011
baj nj theo t la thay zo.thu dj,dc do.ngjem dep cuk
07:26:00 06/08/2011
thay zo dc nj nay:x(x+1)(x6-2x5+2x4+1)=0 pt thu3 lun >0 hjhj
17:11:00 06/08/2011
O.dung oy do.
22:55:00 06/08/2011
Can bac 3 (1+x)+can bac 2 (1-y)=2 va x^2-y^4+9y=x(9+y-y^3)
11:22:00 07/08/2011
pt2<=> (x-y)(x+y3-9)=0 .th1:the x=y vao pt1,sau do dat a=can b3 (1+x),b=cb2(1-x) =>co he:a+b=2 va a3+b2=2.gjaj tjp.
11:27:00 07/08/2011
th2:the x=9-y3 vao pt1 dc: cb3(10-y3) + cb2(1-y) =2 .ta co VT >= cb3(9)>2 ¥ y<=1 .ok
11:59:00 07/08/2011
Ukm.hj